PHYSICS

A stone is thrown from the edge of a cliff into the ocean below. The stone is thrown horizontally outward. The stone has a mass of 2.00 kilograms (kg) and is thrown with a speed of 10.0 meters per second (m/s) from an initial height of 5.00 meters (m) above the ocean. What is the speed with which the stone hits the water?

Initial horizontal velocity = 10 m/s, Initial vertical velocity = 0

Time taken to reach the Ocean = 5 m, can be calculated using the relation, S = u t + ½ a t²

5 = ½ x 9.8 x t²

t² = 5 / 4.9

t² = 1.020

t = 1 seconds

V_y = Uy + g t

V_y = 0 + x 9.8 x 1

V_y = 9.8 m/s

Vx = Ux = 10 m/s

Vx = 10 m/s

Resultant velocity =

V = 14 m/s